This is a frequent request in newsgroups and fora. People want to sort the column in ascending order but don't want the NULLS at the beginning.
Oracle has this syntax: ORDER BY ColumnName NULLS LAST;
SQL Server does not have this. But there are 2 ways to do this. The first one is by using case and the second one by using COALESCE and the maximum value for the data type in the order by clause.
The 2 approaches with a datetime data type
DECLARE @Temp table(Col datetime)
INSERT INTO @Temp VALUES(getdate())
INSERT INTO @Temp VALUES('2007-10-19 09:54:03.730')
INSERT INTO @Temp VALUES('2006-10-19 09:54:03.730')
INSERT INTO @Temp VALUES('2005-10-19 09:54:03.730')
INSERT INTO @Temp VALUES('2006-10-19 09:54:03.730')
INSERT INTO @Temp VALUES('2004-10-19 09:54:03.730')
INSERT INTO @Temp VALUES(NULL)
INSERT INTO @Temp VALUES(NULL)
SELECT *
FROM @Temp
ORDER BY COALESCE(Col,'9999-12-31 23:59:59.997')
SELECT *
FROM @Temp
ORDER BY CASE WHEN Col Is NULL Then 1 Else 0 End, Col
The 2 approaches with an integer data type
DECLARE @Temp table(Col int)
INSERT INTO @Temp VALUES(1)
INSERT INTO @Temp VALUES(555)
INSERT INTO @Temp VALUES(444)
INSERT INTO @Temp VALUES(333)
INSERT INTO @Temp VALUES(5656565)
INSERT INTO @Temp VALUES(3)
INSERT INTO @Temp VALUES(NULL)
INSERT INTO @Temp VALUES(NULL)
SELECT *
FROM @Temp
ORDER BY COALESCE(Col,'2147483647')
SELECT *
FROM @Temp
ORDER BY CASE WHEN Col Is NULL Then 1 Else 0 End, Col